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How much cement required for m25 concrete?

1 Answer
V
Vibha Garg

  The amount of cement required for M25 concrete depends on the mix ratio specified for M25 grade concrete. For M25 grade concrete, the mix ratio is generally 1:1:2, which means 1 part cement, 1 part fine aggregate (such as sand), and 2 parts coarse aggregate (such as crushed stone or gravel). To calculate the quantity of cement needed for M25 concrete, you can use the following formula: Cement Quantity = (Volume of concrete) x (Ratio of cement in the mix).  The volume of concrete can be determined by multiplying the length, width, and height of the concrete structure or by using any other appropriate measurement method.  For example, if you have a concrete structure with dimensions of 10 feet (length) x 8 feet (width) x 6 inches (height), the volume of concrete would be: Volume of concrete = 10 ft x 8 ft x (6 inches / 12 inches/ft) = 40 ft³.  Assuming a mix ratio of 1:1:2 for M25 concrete, the cement quantity would be: Cement Quantity = 40 ft³ x 1/4 = 10 ft³.  To convert the cement quantity from cubic feet to bags, you can divide it by the standard volume of cement in one bag (usually 1 cubic foot).  It is important to note that these calculations are approximate and can vary depending on specific project requirements and the availability of locally preferred practices. It is advisable to consult with a qualified engineer or construction professional to determine the precise cement quantity for your M25 concrete mix.

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